# Bauhaus-Universität Weimar

### Volltext Natural inheritance

Titel:
Natural inheritance
Person:
Galton, Francis
PURL:
https://digitalesammlungen.uni-weimar.de/viewer/image/lit26699/210/
```TABLES.
203
Table 6.
Values of the Probability Integral for Argument ^ ; that is, when the unit
of measurement = the Probable error.
Multiples
of the
Probable
Error.
•0
T
■2
•3
'4
•5
•6
•7
•s
•9
0
o-oo
0-65
Oil
0*16
0-21
0 26
0'31
0-36
0-41
' 0-46
10
•60
•64
•58
■62
•66
•69
•72
•75
•78
•80
2-0
•82
■84
■86
.88
•89
•91
•92
•93
•94
•95
3-0
•967
.964
•969
•974
•978
•982
■985
•987
•990
•992
4-0
•9930
.9943
•9954
•9963
•9970
•9976
■9981
•9985
•9988
•9990
5-0
•9993
•9994
•9996
•9997
•9997
■9998
•9993
■9999
•9999
•9999
infinite
1-000
Tables 5 and 6 show the proportion of eases in any Normal
system, in -which the amount of Error lies within various extreme
values, the total number of cases being reckoned as 1 0. Here no re¬
gard is paid to the sign of the Error, whether it be plus or minus, but
its amount is alone considered. The unit of the scale by which the
Errors are measured, differs in the two Tables. In Table 5 it is
the ‘'Modulus,” and the result is that the Errors in one half of the
cases, that is in 0 Ö0 of them lie within the extreme value (found by
interpolation) of 0-4769, while the other half exceed that value.
In Table 6 the unit of the scale is 0'4769. It is derived from Table
5 by dividing all the tabular entries by that amount. Consequently
one half of the cases have Errors that do not exceed TO in terms of
the new unit, and that unit is the Probable Error of the System.
It will be seen in Table 6 that the entry of ’50 stands opposite to
the argument of TO.
If it be desired to transform Tables 5 and 6 into others that shall
show the proportion of cases in which the plus Errors and the minus
Errors respectively lie within various extreme limits, their entries
would have to be halved.
Let us suppose this to have been done to Table 6, and that a
new Table, which it is not necessary to print, has been thereby pro¬
duced and which we will call 6a. Next multiply all the entries in the
new Table by 100 in order to make them refer to a total number
of 100 cases, and call this second Table 65. Lastly make a converse
Table to 65 ; one in which the arguments of 65 become the entries,
and the entries of 65 become the arguments. From this the Table 7
```

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